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2000x-60x^2=0
a = -60; b = 2000; c = 0;
Δ = b2-4ac
Δ = 20002-4·(-60)·0
Δ = 4000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4000000}=2000$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2000)-2000}{2*-60}=\frac{-4000}{-120} =33+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2000)+2000}{2*-60}=\frac{0}{-120} =0 $
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